FreeBSD kernel libkern code
strlen.c
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1/*-
2 * SPDX-License-Identifier: BSD-2-Clause-FreeBSD
3 *
4 * Copyright (c) 2009, 2010 Xin LI <delphij@FreeBSD.org>
5 *
6 * Redistribution and use in source and binary forms, with or without
7 * modification, are permitted provided that the following conditions
8 * are met:
9 * 1. Redistributions of source code must retain the above copyright
10 * notice, this list of conditions and the following disclaimer.
11 * 2. Redistributions in binary form must reproduce the above copyright
12 * notice, this list of conditions and the following disclaimer in the
13 * documentation and/or other materials provided with the distribution.
14 *
15 * THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS'' AND
16 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
17 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
18 * ARE DISCLAIMED. IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
19 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
20 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
21 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
22 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
23 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
24 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
25 * SUCH DAMAGE.
26 */
27
28#include <sys/cdefs.h>
29__FBSDID("$FreeBSD$");
30
31#include <sys/libkern.h>
32#include <sys/limits.h>
33
34/*
35 * Portable strlen() for 32-bit and 64-bit systems.
36 *
37 * The expression:
38 *
39 * ((x - 0x01....01) & ~x & 0x80....80)
40 *
41 * would evaluate to a non-zero value iff any of the bytes in the
42 * original word is zero.
43 *
44 * The algorithm above is found on "Hacker's Delight" by
45 * Henry S. Warren, Jr.
46 *
47 * Note: this leaves performance on the table and each architecture
48 * would be best served with a tailor made routine instead, even if
49 * using the same trick.
50 */
51
52/* Magic numbers for the algorithm */
53#if LONG_BIT == 32
54static const unsigned long mask01 = 0x01010101;
55static const unsigned long mask80 = 0x80808080;
56#elif LONG_BIT == 64
57static const unsigned long mask01 = 0x0101010101010101;
58static const unsigned long mask80 = 0x8080808080808080;
59#else
60#error Unsupported word size
61#endif
62
63#define LONGPTR_MASK (sizeof(long) - 1)
64
65/*
66 * Helper macro to return string length if we caught the zero
67 * byte.
68 */
69#define testbyte(x) \
70 do { \
71 if (p[x] == '\0') \
72 return (p - str + x); \
73 } while (0)
74
75size_t
76(strlen)(const char *str)
77{
78 const char *p;
79 const unsigned long *lp;
80 long va, vb;
81
82 /*
83 * Before trying the hard (unaligned byte-by-byte access) way
84 * to figure out whether there is a nul character, try to see
85 * if there is a nul character is within this accessible word
86 * first.
87 *
88 * p and (p & ~LONGPTR_MASK) must be equally accessible since
89 * they always fall in the same memory page, as long as page
90 * boundaries is integral multiple of word size.
91 */
92 lp = (const unsigned long *)((uintptr_t)str & ~LONGPTR_MASK);
93 va = (*lp - mask01);
94 vb = ((~*lp) & mask80);
95 lp++;
96 if (va & vb)
97 /* Check if we have \0 in the first part */
98 for (p = str; p < (const char *)lp; p++)
99 if (*p == '\0')
100 return (p - str);
101
102 /* Scan the rest of the string using word sized operation */
103 for (; ; lp++) {
104 va = (*lp - mask01);
105 vb = ((~*lp) & mask80);
106 if (va & vb) {
107 p = (const char *)(lp);
108 testbyte(0);
109 testbyte(1);
110 testbyte(2);
111 testbyte(3);
112#if (LONG_BIT >= 64)
113 testbyte(4);
114 testbyte(5);
115 testbyte(6);
116 testbyte(7);
117#endif
118 }
119 }
120
121 /* NOTREACHED */
122 return (0);
123}
size_t() strlen(const char *str)
Definition: strlen.c:76
#define testbyte(x)
Definition: strlen.c:69
__FBSDID("$FreeBSD$")